1.

A solution is prepared by dissolving 18.25 g NaOH in 200 mL of it. Calculate the molarity of the solution.

Answer»


Solution :MOLARITY of solution (M) `=(("Mass of NaOH")/("MOLECULAR mass of NaOH"))/("Volume of solution in mL"/(1000))=((18.25g))/(("40 g mol"^(-1))xx("0.2 L"))`
`= 2.281 "mol L"^(-1) = 2.281 M`.


Discussion

No Comment Found