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A solution is prepared by dissolving 2.0 g of glucose and 4.0 g urea in 100 g of water at 298 K . Calculate the vapour pressure of the solution ,If the vapour pressure of pure water is23.756 torr. (Molecular mass of urea = 60 and glucose= 180g mol^(-1))

Answer» <html><body><p>&lt;<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>&gt;</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(i)`x_A =( n_A)/( n_A+n_B)` <br/> ` n_A ="No of moles <a href="https://interviewquestions.tuteehub.com/tag/water-1449333" style="font-weight:bold;" target="_blank" title="Click to know more about WATER">WATER</a> "` <br/> `n_B = "No. of <a href="https://interviewquestions.tuteehub.com/tag/molesof-2840420" style="font-weight:bold;" target="_blank" title="Click to know more about MOLESOF">MOLESOF</a> glucose " ` <br/>`n_A =( 100)/( <a href="https://interviewquestions.tuteehub.com/tag/18-278913" style="font-weight:bold;" target="_blank" title="Click to know more about 18">18</a> ) = 5.555` <br/> ` n_B =(2)/( 180) = 0.0111` <br/> Total moles ` (n_A+n_B) = 5.566` <br/> (ii)Urea <br/> ` n_A = "No. of moles of water " ` <br/> ` n_B=" No. of mole of urea " ` <br/> `n_A = 5.555` <br/> ` n_B=( 4)/( 60) = 0.0666 " moles of urea "` <br/> Total moles ` = 0.555+ 0.066 moles ` <br/> `x_B = ( n_A)/( n_A+n_B) ` <br/> `= ( 5.555)/( 5.621) = 0.9882` <br/> `P_B = P^(@) xx x_B ` <br/> `""= 23.756xx 0.9882` <br/> ` P_B = 23.42 torr`</body></html>


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