A solution is prepared by dissolving 46 g of ethyl alcohol in 90 g of water. The mole fraction of ethyl alcohol in this solution is:

A solution is prepared by dissolving 46 g of ethyl alcohol in 90 g of

1.	A solution is prepared by dissolving 46 g of ethyl alcohol in 90 g of water. The mole fraction of ethyl alcohol in this solution is:
Answer» <html><body><p>`46/<a href="https://interviewquestions.tuteehub.com/tag/90-341351" style="font-weight:bold;" target="_blank" title="Click to know more about 90">90</a>`<br/>`90/46`<br/>`46/(90 + 46)`<br/>`1/6`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :No. of moles `(n_(A))` of ethyl alcohol = `46/46=1` <br/> No. of moles `(n_(B))` of <a href="https://interviewquestions.tuteehub.com/tag/water-1449333" style="font-weight:bold;" target="_blank" title="Click to know more about WATER">WATER</a> `=90/18=5` <br/> `therefore` Mole <a href="https://interviewquestions.tuteehub.com/tag/fractioni-2657546" style="font-weight:bold;" target="_blank" title="Click to know more about FRACTIONI">FRACTIONI</a> of ethyl alcohol `=n_(A)/(n_(A) + n_(B)) = 1/(1+5) = 1/6`</body></html>