A solution is prepared by dissolving 46 g of ethyl alcohol in 90 g of water. The mole fraction of ethyl alcohol in this solution is:

A solution is prepared by dissolving 46 g of ethyl alcohol in 90 g of

1.	A solution is prepared by dissolving 46 g of ethyl alcohol in 90 g of water. The mole fraction of ethyl alcohol in this solution is:
Answer» `46/90` `90/46` `46/(90 + 46)` `1/6` SOLUTION :No. of moles `(n_(A))` of ethyl alcohol = `46/46=1` No. of moles `(n_(B))` of WATER `=90/18=5` `therefore` Mole FRACTIONI of ethyl alcohol `=n_(A)/(n_(A) + n_(B)) = 1/(1+5) = 1/6`