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A solution is saturated with respect to SrCO_3 and SrF_2. The [CO_3^(2-)] was found to be1.2 xx 10^(-3)M.The concentration of F^(-)in the solution would be :(K_(sp)of SrCO_3 = 7xx 10^(-10)K_(sp)of SrF_2 =8xx 10^(-10))

Answer» <html><body><p>` 1.3 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-3) M` <br/>` <a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>.6 xx 10^(-2)M` <br/>` 3.7 xx 10^(-2) M` <br/>` 5.8 xx 10^(-7) M` </p>Solution :`[Sr^(+2) ][CO_3^(2-)] =KsP_1 ,[Sr^(+2) ][<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a>^(-) ] ^(2) = Ksp_2` <br/> `rArr [F^(-) ]^(2) =(Ksp_2)/(Ksp_1) xx [CO_3^(2-)]` <br/> ` [F^(-)]^(2)=(8xx 10^(-10))/( 7 xx 10 ^(-10)) xx 1.2 xx 10 ^(-3)` <br/> ` [F^(-)] =3.7 xx 10 ^(-2)`</body></html>


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