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A solution is0.01 M Kland 0. 1 M KCl . If solidAgNO_3is added to the solution, what is the [1^(-) ] when AgClbegins to precipitate[K_(sp) (Agl) =1.5 xx 10^(-16) , K_(sp)(AgCl) =1.8 xx 10^(-10)] |
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Answer» ` 3.5 xx 10^(-7)` ` [Ag^(+) ] =(1.8 xx 10^(-10))/( 10^(-1) )= 1.8 xx 10^(-9) ` ` [I^(-) ]=(K_(sp) )/( [Ag^(+) ]_(cl^(-) ))=(1.5 xx10^(-16))/( 1.8 xx 10^(-19)) = 8.3 xx 10 ^(-8) M` |
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