A solution of 10 mL of (M)/(10) FeSO_(4) was titrated with KMnO_(4) solution in acidic medium, the amount of KMnO_(4) used will be :

A solution of 10 mL of (M)/(10) FeSO_(4) was titrated with KMnO_(4) so

1.	A solution of 10 mL of (M)/(10) FeSO_(4) was titrated with KMnO_(4) solution in acidic medium, the amount of KMnO_(4) used will be :
Answer» <html><body><p>10 mL of 0.5 M<br/>10 mL of 0.<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> M<br/>10 mL of 0.02 M<br/>5 mL of 0.1 M</p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/involved-7257329" style="font-weight:bold;" target="_blank" title="Click to know more about INVOLVED">INVOLVED</a> reaction is : <br/> `2KMnO_(4)+8H_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)SO_(4)+10FeSO_(4) to 5Fe_(2)(SO_(4))_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)+2MnSO_(4)+K_(2)SO_(4)+8H_(2)O` <br/> `(M_(1)V_(1))/(2)=(0.1xx10)/(10)` <br/> `M_(1)V_(1)=0.2` which is possible in (c )</body></html>