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A solution of ethanol in water is 1.6 molal. How many grams of ethanol are present in 500 g of the solution ? |
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Answer» Solution :1.6 m solution would contain 1.6 MOLES of ETHANOL dissolved in 1000 g of water. Molecular mass of ethanol `(C_(2)H_(5)OH) = 46` Mass of ethanol dissolved = `46 XX 1.6 = 73.6` g Total mass of solution = `73.6 + 1000 = 1073.6` g THUS, 1073.6 g of solution contain 73.6 g of ethanol. Hence, the mass of ethanol present in 500 g of the solution `=73.6/(1073.6)xx 500 = 34.28 g` |
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