A solution of ferrous oxalate has been prepared by dissoliving 3.6 g L^(-1) calculate the volume of 0.01 M KMnO_(4) solution required for complete oxidatin of 100 mL of lferrous oxalte soluton in acidic medium

A solution of ferrous oxalate has been prepared by dissoliving 3.6 g L

1.	A solution of ferrous oxalate has been prepared by dissoliving 3.6 g L^(-1) calculate the volume of 0.01 M KMnO_(4) solution required for complete oxidatin of 100 mL of lferrous oxalte soluton in acidic medium
Answer» <html><body><p><br/></p>Solution :Molarity of `FeC_(2)O_(4)` solution `=("mass in" gL^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>))/("<a href="https://interviewquestions.tuteehub.com/tag/mol-1100196" style="font-weight:bold;" target="_blank" title="Click to know more about MOL">MOL</a> mass in" <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> mol^(-1))=(3.6)/(144)=0.025M` <br/> The balanced chemical equation for the redox reaction is : <br/> `5FeC_(2)O_(4)+3MinO_(4)^(2-)+24H^(+)rarr5Fe^(3+)+<a href="https://interviewquestions.tuteehub.com/tag/3mn-1863569" style="font-weight:bold;" target="_blank" title="Click to know more about 3MN">3MN</a>^(2+)10CO_(2)+12H_(2)O` <br/> Applying molarity equation we have <br/> `(0.01xxV)/(3)(MnO_(4)^(-))=(0.025xx100)/(5)(FeC_(2)O_(4)) "in" V=(0.025xx100xx3)/(5xx0.01)=150 mL`</body></html>