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InterviewSolution
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A solution of glucose in water is labelled as `10 "percent" w//w`, what would be the molality and mole fraction of each component in the solution? If the density of the solution is `1.2 g mL^(-1)`, then what shall be the molarity of the solution? |
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Answer» 10 percent w/w solution of glucose I water means 10 g glucose and 90 g of water. Molar mass of glucose`=180g" "mol^(-1)` and molar mass of water `=18" "mol^(-1)`. `10g` of glucose `=(10)/(180=0.0555` moles and 90g of `H_(2)O=(90)/(18)=5` moles `therefore` molality of solution `=("Moles of solute"xx1000)/("Mass of solution in grams")` `=(0.555)/(90)xx1000=0*617`m Mole fraction of glucose. Mole fraction of glucose. `=X_(g)=("No of moles of glucose")/("No. of moles+No. of moles of glucose of water")` `=(0*0555)/(5+0*0555)=0.01` mole fraction of water `X_(w)=("No. of moles of water")/("No. of moles+No. of glucose moles of water")` `=(5)/(5+0*0555)=0*99` Volume of 100g of solution `=("Mass of solution")/("Density")=(100)/(1*2)=83*33mL` `therefore` Molarity of solution `=(0*0555)/(83*33)xx1000` `=0*67M`. |
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