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A solution of glycine hydrochloride contains the chloride ion and the glycinium ion, .^(+)NH_(3) - CH_(2) - COOH, which is a diprotic acid, H_(3)N^(+) -CH_(2) - COOH + H_(2)O hArr H_(3)N^(+) - CH_(2) - COO^(-) + H_(3)O^(+), K_(1) = 4.47 x10^(-3) H_(3)N^(+) - CN_(2) - COO^(-) + H_(2)O hArr H_(2)N - CH_(2) - COO^(-) + H_(3)O^(+), K_(2) = 1.66x10^(-10) Calculate pH of a 0.05 M of glycine hydrochloride.

Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>.89`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>.52`<br/>`8.91`<br/>`9.18`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`(<a href="https://interviewquestions.tuteehub.com/tag/ph-1145128" style="font-weight:bold;" target="_blank" title="Click to know more about PH">PH</a> =pKa_(1) + pKa_(2))/(2)`</body></html>


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