A solution of m-chloroaniline, m-chlorophenol, m-chlorobenzoic acid in ethyl acetate was extracted initially with a saturated solution of NaHCO_(3) to give fraction A, the leftover organic phase was extracted with dil. NaOH to give fraction B. The final organic layer was labelled as fraction C. Fractions A, B and C contains respectively.

A solution of m-chloroaniline, m-chlorophenol, m-chlorobenzoic acid in

1.	A solution of m-chloroaniline, m-chlorophenol, m-chlorobenzoic acid in ethyl acetate was extracted initially with a saturated solution of NaHCO_(3) to give fraction A, the leftover organic phase was extracted with dil. NaOH to give fraction B. The final organic layer was labelled as fraction C. Fractions A, B and C contains respectively.
Answer» m-chlorobenzoic ACID, m-chlorophenol and m-chloroaniline m-chlorophenol, m-chlorobenzoic acid and m-chloroaniline m-chloroaniline, m-chlorophenol and m-chlorobenzoic acid m-chlorobenzoic acid, m-chloroaniline and m-chlorophenol Solution :m-chlorobenzoic acid being the most ACIDIC can be separated by a weak base like `NaHCO_(3)` and HENCE will be labelled FRACTION A. m-chlorophenol is not as acidic as m-chlorobenzoic acid, and can be separated by a stronger base like NaOH, and hence can be labelled as fraction B. m-chloroaniline being a base, does not react with either of the bases and hence would be labelled as fraction C