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A solution of m-chloroaniline, m-chlorophenol, m-chlorobenzoic acid in ethyl acetate was extracted initially with a saturated solution of NaHCO_(3) to give fraction A, the leftover organic phase was extracted with dil. NaOH to give fraction B. The final organic layer was labelled as fraction C. Fractions A, B and C contains respectively.

Answer» <html><body><p>m-chlorobenzoic <a href="https://interviewquestions.tuteehub.com/tag/acid-847491" style="font-weight:bold;" target="_blank" title="Click to know more about ACID">ACID</a>, m-chlorophenol and m-chloroaniline<br/>m-chlorophenol, m-chlorobenzoic acid and m-chloroaniline<br/>m-chloroaniline, m-chlorophenol and m-chlorobenzoic acid<br/>m-chlorobenzoic acid, m-chloroaniline and m-chlorophenol</p>Solution :m-chlorobenzoic acid being the most <a href="https://interviewquestions.tuteehub.com/tag/acidic-847601" style="font-weight:bold;" target="_blank" title="Click to know more about ACIDIC">ACIDIC</a> can be separated by a weak base like `NaHCO_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)` and <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a> will be labelled <a href="https://interviewquestions.tuteehub.com/tag/fraction-458259" style="font-weight:bold;" target="_blank" title="Click to know more about FRACTION">FRACTION</a> A. m-chlorophenol is not as acidic as m-chlorobenzoic acid, and can be separated by a stronger base like NaOH, and hence can be labelled as fraction B. m-chloroaniline being a base, does not react with either of the bases and hence would be labelled as fraction C</body></html>


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