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A solution of Na_2S_2O_3 is standardised iodometrically by using K_2Cr_2O_7. The equivalent weight of K_2Cr_2O_7 in this method is:

Answer» <html><body><p>Mol. Wt/<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a><br/>Mol. Wt/<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a><br/>Mol. Wt/<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a><br/>equal to mol wt. </p>Solution :`Cr_(2)O_(<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a>)^(2-) to 2Cr^(3+)` <a href="https://interviewquestions.tuteehub.com/tag/eq-446394" style="font-weight:bold;" target="_blank" title="Click to know more about EQ">EQ</a>. wt. `=("Mol wt")/6`</body></html>


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