A solution which is 10^(-3) M each in Mn^(2+), Fe^(2+), Zn^(2+) and Hg^(2+) is treated with 10^(-16) M sulphide ion. If K_(sp) of MnS, FeS, ZnS and HgS are 10^(-15), 10^(-23), 10^(-20) and 10^(-54) respectively, which one will precipitate first ?

A solution which is 10^(-3) M each in Mn^(2+), Fe^(2+), Zn^(2+) and Hg

1.	A solution which is 10^(-3) M each in Mn^(2+), Fe^(2+), Zn^(2+) and Hg^(2+) is treated with 10^(-16) M sulphide ion. If K_(sp) of MnS, FeS, ZnS and HgS are 10^(-15), 10^(-23), 10^(-20) and 10^(-54) respectively, which one will precipitate first ?
Answer» <html><body><p>FeS<br/>MgS<br/>HgS<br/>ZnS</p>Solution :`HgS` will be <a href="https://interviewquestions.tuteehub.com/tag/precipitated-2948214" style="font-weight:bold;" target="_blank" title="Click to know more about PRECIPITATED">PRECIPITATED</a> <a href="https://interviewquestions.tuteehub.com/tag/first-461760" style="font-weight:bold;" target="_blank" title="Click to know more about FIRST">FIRST</a> because [its `K_(sp)`] is <a href="https://interviewquestions.tuteehub.com/tag/minimum-561095" style="font-weight:bold;" target="_blank" title="Click to know more about MINIMUM">MINIMUM</a>.</body></html>