A solution which is 10^(-3) M each in Mn^(2+), Fe^(2+), Zn^(2+) and Hg^(2+) is treated with 10^(-16) M sulphide ion. If K_(sp) of MnS, FeS, ZnS and HgS are 10^(-15), 10^(-23), 10^(-20) and 10^(-54) respectively, which one will precipitate first ?

A solution which is 10^(-3) M each in Mn^(2+), Fe^(2+), Zn^(2+) and Hg

1.	A solution which is 10^(-3) M each in Mn^(2+), Fe^(2+), Zn^(2+) and Hg^(2+) is treated with 10^(-16) M sulphide ion. If K_(sp) of MnS, FeS, ZnS and HgS are 10^(-15), 10^(-23), 10^(-20) and 10^(-54) respectively, which one will precipitate first ?
Answer» FeS MgS HgS ZnS Solution :`HgS` will be PRECIPITATED FIRST because [its `K_(sp)`] is MINIMUM.