A solution which remains in equilibrium with undissolved solute is said to be saturated. The concentration of a saturated solution at a given temperature is called solubility. The product of concentration of ions in a saturated solution of an electrolyte at a given temperature, is called solubility product (K_(sp)). For the electrolyte, A_(x),B_(y),:A_(x),B_(y(s)) rarr xA^(y+)+ y^(Bx-), with solubility S, the solubility product (K_(sp)) =x^(x)xxy^(y) xx s^(x+y). While calculating the solubility of a sparingly soluble salt in the presence of some strong electrolyte containing a common ion, the common ion concentration is practically equal to that of strong electrolyte. If in a solution, the ionic product of an clectrolyte exceeds its K_(sp), value at a particular temperature, then precipitation occurs. The solubility of PbSO_(4), in water is 0.303 g/l at 25^(@)C, its solubility product at that temperature is

A solution which remains in equilibrium with undissolved solute is sai

1.	A solution which remains in equilibrium with undissolved solute is said to be saturated. The concentration of a saturated solution at a given temperature is called solubility. The product of concentration of ions in a saturated solution of an electrolyte at a given temperature, is called solubility product (K_(sp)). For the electrolyte, A_(x),B_(y),:A_(x),B_(y(s)) rarr xA^(y+)+ y^(Bx-), with solubility S, the solubility product (K_(sp)) =x^(x)xxy^(y) xx s^(x+y). While calculating the solubility of a sparingly soluble salt in the presence of some strong electrolyte containing a common ion, the common ion concentration is practically equal to that of strong electrolyte. If in a solution, the ionic product of an clectrolyte exceeds its K_(sp), value at a particular temperature, then precipitation occurs. The solubility of PbSO_(4), in water is 0.303 g/l at 25^(@)C, its solubility product at that temperature is
Answer» ` 10^(-4)M^(2) ` ` 9.18 xx 10^(-4) M` ` 10^(-6)M^(2)` ` 9.18 xx 10^(-8) M^(2)` Solution :` S= 0.303 g // lit ` ` MOL . WT = 207 + 32 + 64 =303 ` MOLES ` =( 0.303)/( 303)=10 ^(-3) ` ` S = 10 ^(-3)" MOLE " // "lit"` ` pbSO_4 hArr Punderset(S) b^(+2)+Sunderset( S) O ^(-2), S =10 ^(-3) ` ` K_(sp)= ( 10 ^(-3) M)^(2) =10 ^(-6)M^(2) `