A sparingly soluble salt having general formula A_x^(p+) B_y^(q-)and molar solubility S is in equilibrium with its saturated solution. Derive a relationship between solubility and the solubility product for such salt.

A sparingly soluble salt having general formula A_x^(p+) B_y^(q-)and m

1.	A sparingly soluble salt having general formula A_x^(p+) B_y^(q-)and molar solubility S is in equilibrium with its saturated solution. Derive a relationship between solubility and the solubility product for such salt.
Answer» Solution :A sparingly soluble salt having general formula `A_x^(p+) B_y^(q-)` . Its MOLAR solubilityis S mol `L^(-1)` . Then, `A_x^(p+) B_y^(q-)hArr xA_x^(p+)(AQ)+yB_y^(q-)` (aq) S moles of `A_xB_y` dissolve to give X moles of `A^(p+)` and y moles of `B^(q-)` Therefore , solubility PRODUCT `(K_(sp))=[A^(p+)]^x [B^(q-)]^y` `=[xS]^x [yS]^y` `=x^x y^y S^(x+y)`