A sparingly soluble salt having general formula A_x^(p+) B_y^(q-)and molar solubility S is in equilibrium with its saturated solution. Derive a relationship between solubility and the solubility product for such salt.

A sparingly soluble salt having general formula A_x^(p+) B_y^(q-)and m

1.	A sparingly soluble salt having general formula A_x^(p+) B_y^(q-)and molar solubility S is in equilibrium with its saturated solution. Derive a relationship between solubility and the solubility product for such salt.
Answer» <html><body><p></p>Solution :A sparingly soluble salt having general formula `A_x^(p+) B_y^(q-)` . Its <a href="https://interviewquestions.tuteehub.com/tag/molar-562965" style="font-weight:bold;" target="_blank" title="Click to know more about MOLAR">MOLAR</a> solubilityis S mol `L^(-1)` . <br/> Then, `A_x^(p+) B_y^(q-)hArr xA_x^(p+)(<a href="https://interviewquestions.tuteehub.com/tag/aq-883254" style="font-weight:bold;" target="_blank" title="Click to know more about AQ">AQ</a>)+yB_y^(q-)` (aq) <br/> S moles of `A_xB_y` dissolve to give <a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a> moles of `A^(p+)` and y moles of `B^(q-)` <br/> Therefore , solubility <a href="https://interviewquestions.tuteehub.com/tag/product-25523" style="font-weight:bold;" target="_blank" title="Click to know more about PRODUCT">PRODUCT</a> <br/> `(K_(sp))=[A^(p+)]^x [B^(q-)]^y` <br/> `=[xS]^x [yS]^y` <br/> `=x^x y^y S^(x+y)`</body></html>