1.

A special die is so constructed that the probabilities of throwing 1, 2, 3, 4, 5 and 6 are (1-k)/(6), (1+2k)/(6), (1-k)/(6), (1+k)/(6), (1-2k)/(6) and (1+k)/(6), respectively. If two such thrown and the probability of getting a sum equal to lies between (1)/(9) and (2)/(9), then the integral value of k is

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