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A spherical balloon of 21 cm diameter is to be filled with hydrogen at NTP from a cylinder containing the gas at20 atmosphere at 27^(@)C.If the cylinder can hold 2.82 litres of water, calculate the number of balloons that can be filled up.

Answer» <html><body><p></p>Solution :Volume of the balloon `=(4)/(3)pi r^(3)=(4)/(3)<a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a>(22)/(7)xx((21)/(2))^(3)=4851 cm^(3)` <br/> Volume of the cylinder =2.82 litres=2820 `cm^(3)` <br/> Pressure =20 <a href="https://interviewquestions.tuteehub.com/tag/atm-364409" style="font-weight:bold;" target="_blank" title="Click to know more about ATM">ATM</a>. Temperature =300 K <br/> Converting this to the volume at NTP, <br/> `(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2)):. (20xx2820)/(300)=(1xxV_(2))/(273)"or"V_(2)=51324" cm"^(3)`. <br/> When the pressure in the cylinder is <a href="https://interviewquestions.tuteehub.com/tag/reduced-1181337" style="font-weight:bold;" target="_blank" title="Click to know more about REDUCED">REDUCED</a> to one atmosphere,no more `H_(2)` will be released and hence 2820 `cm^(3)` of `H_(2)` will be left in it. Hence, volume of `H_(2)`used in filling the balloons <br/> `=51324-2820 cm^(3)=<a href="https://interviewquestions.tuteehub.com/tag/4850br4-1880139" style="font-weight:bold;" target="_blank" title="Click to know more about 48504">48504</a> cm^(3)`. <br/> Number of balloons filled =48504/4851=10</body></html>


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