A spring gun of spring constant 90 N cm^(-1) is compressed 12 cm by a ball of mass 16 g. If the trigger is pulled, the velocity of the ball is

A spring gun of spring constant 90 N cm^(-1) is compressed 12 cm by a

1.	A spring gun of spring constant 90 N cm^(-1) is compressed 12 cm by a ball of mass 16 g. If the trigger is pulled, the velocity of the ball is
Answer» <html><body><p>`50 m s^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`<br/>`40 <a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a>^(-1)`<br/>`60 m s^(-1)`<br/>`90 ms^(-1)`</p>Solution :Here , `m = 16 g = 16 xx 10^(-3) kg` <br/>`k = 90 N cm^(-1) = 90 xx 10 Nm^(-1)` <br/>`x = 12 cm = 12 xx 10^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) m` <br/> According to the law of <a href="https://interviewquestions.tuteehub.com/tag/conservation-929810" style="font-weight:bold;" target="_blank" title="Click to know more about CONSERVATION">CONSERVATION</a> of energy, <br/> `1/2 mv^2 = 1/2 kx^2 " or " <a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>^2 = (kx^2)/(m)` <br/> or `v = xsqrt(k/m) (12 xx 10^(-2)m) sqrt((90 xx 100 Nm^(-1))/(16 xx 10^(-3) kg)) = 90 ms^(-1)`. <br/> Thus the velocity of the ball `90 ms^(-1)`.</body></html>