1.

A spring gun of spring constant 90 N cm^(-1) is compressed 12 cm by a ball of mass 16 g. If the trigger is pulled, the velocity of the ball is

Answer»

`50 m s^(-1)`
`40 MS^(-1)`
`60 m s^(-1)`
`90 ms^(-1)`

Solution :Here , `m = 16 g = 16 xx 10^(-3) kg`
`k = 90 N cm^(-1) = 90 xx 10 Nm^(-1)`
`x = 12 cm = 12 xx 10^(-2) m`
According to the law of CONSERVATION of energy,
`1/2 mv^2 = 1/2 kx^2 " or " V^2 = (kx^2)/(m)`
or `v = xsqrt(k/m) (12 xx 10^(-2)m) sqrt((90 xx 100 Nm^(-1))/(16 xx 10^(-3) kg)) = 90 ms^(-1)`.
Thus the velocity of the ball `90 ms^(-1)`.


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