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A spring, which is initially in its unstretched condition, is first stretched by a length x and then again by a further length x. The work done in the first case is W_1 and in the second case is W_2. Then

Answer» <html><body><p> `W_2 = W_1`<br/>`W_2 = 2W_1`<br/>`W_2 = 3W_1`<br/>`W_2 = <a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> W_1`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Let <a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a> be the force constant of the spring. <br/> Potential energy of the spring after the first <a href="https://interviewquestions.tuteehub.com/tag/stretching-1229374" style="font-weight:bold;" target="_blank" title="Click to know more about STRETCHING">STRETCHING</a> is <br/> `U_1 = 1/2 kx^2` <br/> Potential energy of the spring after the second stretching is <br/> `U_2 = 1/2 k (2x)^2` <br/> `:. W_1 = U_1 = 1/2 kx^2` <br/> and `W_2 = U_2 - U_1 = 1/2 k(2x)^(2) - 1/2 kx^2 = 3(1/2 kx^2) = 3W_1`.</body></html>


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