A square lead slab of side 50 cm and thickness 10 cm is subject to a shearing force (on its narrow face) of 9.0xx10^(4)N. The lower edge is riveted to the floor How much will the upper edge be displaced ?

A square lead slab of side 50 cm and thickness 10 cm is subject to a s

1.	A square lead slab of side 50 cm and thickness 10 cm is subject to a shearing force (on its narrow face) of 9.0xx10^(4)N. The lower edge is riveted to the floor How much will the upper edge be displaced ?
Answer» <html><body><p></p>Solution :The leadslab is fixed and the force is appliedparallelto the narrowface as shownin figure. The areaof the face parallelto which this force is appliedis<br/> `A=50cm xx <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a> =0.05 m^(2)` <br/><a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> the stressapplied is <br/>`=(9.4xx10^(4) //0.05)=1.80 xx 10^(6) N.m^(-2)` <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_PMH_C10_SLV_036_S01.png" width="80%"/><br/>We know thatshearing strain `=(<a href="https://interviewquestions.tuteehub.com/tag/deltax-2570672" style="font-weight:bold;" target="_blank" title="Click to know more about DELTAX">DELTAX</a>//L)="Stress"//G.` <br/> Therefore the dispalcement `Deltax=("Stress"xxL)//G` <br/> `=(1.8xx10^(6)xx0.5)//(5.6xx10^(9))=0.16mm`</body></html>