A steel ball is dropped on a hard surface from a height of `1m` and rebounds to a height of `64cm`. The maximum height attained by the ball after `n^(th)` bounce is (in m)A. (a) `(0.64)^(2n)`B. (b) `(0.8)^(2n)`C. (c) `(0.5)^(2n)`D. (d) `(0.8)^n`

A steel ball is dropped on a hard surface from a height of `1m` and re

1.	A steel ball is dropped on a hard surface from a height of `1m` and rebounds to a height of `64cm`. The maximum height attained by the ball after `n^(th)` bounce is (in m)A. (a) `(0.64)^(2n)`B. (b) `(0.8)^(2n)`C. (c) `(0.5)^(2n)`D. (d) `(0.8)^n`
Answer» Correct Answer - B `h_n=(e^(2n))hi` Given that `(64cm)=(e^2)(100cm)` `:. e=0.8` Substituting in Eq. (i) we have `h_n=(0.8)^(2n)(1m)` `=(0.8)^(2n)`

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A steel ball is dropped on a hard surface from a height of `1m` and rebounds to a height of `64cm`. The maximum height attained by the ball after `n^(th)` bounce is (in m)A. (a) `(0.64)^(2n)`B. (b) `(0.8)^(2n)`C. (c) `(0.5)^(2n)`D. (d) `(0.8)^n`

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