1.

A stone is immersed in a Eureka can. The mass of the empty beaker into which water overflowed was 30 g and the mass of the beaker with the water from the Eureka can is 56 g. If the mass of the stone is 87 g. What is the density of the stone?

Answer»

SOLUTION :`m_1`=30 G , `m_2`=56 g ,
`m_2-m_1`=56-30=26 g
Volume (V)=`26/1= 26 "CM"^3`
m=87 g
Density = `m/((m_2-m_1))=87/26`
`=3.346 "g/cm"^3 = 3.346 xx 1000 "kg/m"^3`
`=3346 "kg/m"^3`


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