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A student forgot to add the reaction mixture to the round bottomed flask at 27^(@)C but instead, he/she placed the flask on the flame. After a lapse of time, he realized his mistake, and using a pyrometer, he found the temperature of the flask was 477^(@)C. What fraction of air would have been expelled out ? |
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Answer» SOLUTION :Suppose VOLUME of vessel =V `cm^(3)`,i.e.,volume of air in the flask at `27^(@)C=V cm^(3)`. `(V_(1))/(T_(1))=(V_(2))/(T_(2)),""i.e.,""(v)/(300)=(V_(2))/(750)"or"V_(2)=2.5" V"` `:. """Volume expelled"=2.5" V"-V=1.5" V"` `:. """Fraction of air expelled" `=(1.5" V")/(2.5" V")=(3)/(5)` |
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