InterviewSolution
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InterviewSolution
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A student very cautiously traces the path of a ray through a glass slab for different values of the angle of incidence `(/_i)`. He then measures the corresponding values of the angle of refraction `(/_r)` and the angle of emergence `(/_e)` for every value of the angle of incidence. On analysing these measurements of angles, his conclusion would beA. `/_i gt /_r gt /_e`B. `/_i= /_e gt /_r`C. `/_i lt /_r lt /_e`D. `/_i= /_e lt /_r` |
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Answer» (b) The correct path of a ray through a glass slab is shown in Fig. As net deviation through the glass slab is zero, therefor `/_i = /_i`. At `B`, the ray goes from a rarer to a denser medium, bends towards normal. Therefore `/_r lt /_i`. or `/_i gt /_r` Hence we conclude that `/_i=/_e gt /_r`. |
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