1.

A swimmer coming out from a pool is covered with a film of water weighing about 18g. How much heat must be supplied to evaporate this water at 298 K? Calculate the internal energy of vaporisation at 100^@C. DeltaH_(vap)^@ for water at 373K = 40.66 kJ mol^(-1)

Answer» <html><body><p></p>Solution :We can represent the <a href="https://interviewquestions.tuteehub.com/tag/process-11618" style="font-weight:bold;" target="_blank" title="Click to know more about PROCESS">PROCESS</a> of <a href="https://interviewquestions.tuteehub.com/tag/evaporation-16312" style="font-weight:bold;" target="_blank" title="Click to know more about EVAPORATION">EVAPORATION</a> as<br/> `H_(2)O_((l)) overset("vaporisation")(rarr)H_2O_((g)) , <a href="https://interviewquestions.tuteehub.com/tag/delta-947703" style="font-weight:bold;" target="_blank" title="Click to know more about DELTA">DELTA</a> = 1 - 0 = 1` <br/> `Delta_(vap) E = Delta_(vap)H - pDeltaV =Delta_(vap) H - DeltanRT` <br/> (assumig steam <a href="https://interviewquestions.tuteehub.com/tag/behaving-2465187" style="font-weight:bold;" target="_blank" title="Click to know more about BEHAVING">BEHAVING</a> as an ideal gas). <br/> `Delta_(vap) E = 40.66 kJ mol^(-1) - (1)` <br/> `(8.314 xx 10^(-3) KJ <a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>^(-1) mol^(-1))(373 K) = 37.56 kJ mol^(-1)`.</body></html>


Discussion

No Comment Found