A synthetic mixture of nitrogen and Argon has a density of 1.4 g L^(-1) at 0^@C. Calculate the average molecular weight. Find out the volume percentage of nitrogen in the mixture.

A synthetic mixture of nitrogen and Argon has a density of 1.4 g L^(-1

1.	A synthetic mixture of nitrogen and Argon has a density of 1.4 g L^(-1) at 0^@C. Calculate the average molecular weight. Find out the volume percentage of nitrogen in the mixture.
Answer» Solution :Molecular weight (M) can be obtained from density (d) as, `M=(dRT)/(P )` Average molecular weight of the mixture =` (1.4 xx 0.0821 xx 273 )/(1) = 31.4` If the % VOLUME of `N_2 ` is .x. ` 31.4 = ( x xx 28+(100-x)40)/( 100 )implies12 x = 840 orx=70` The volume PERCENTAGE of `N_2` in the mixture = 70