1.

A system absorbs 50 kJ heat and does 20 kJ of work. What is the net change in the internal energy of the system ?

Answer»

INCREASE by 30 kJ
Decrease by 30 kJ
Increase by 70 kJ
Decrease by 70 kJ

Solution :`DeltaU=q+(-w)=50+(-20)=30kJ`


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