A system consists of three particles located at the corners of a right triangle as shown in the figure. Find the position vector of centre of mass of the system.

A system consists of three particles located at the corners of a right

1.	A system consists of three particles located at the corners of a right triangle as shown in the figure. Find the position vector of centre of mass of the system.
Answer» Solution : Using the EQUATION `X_(c)=(summ_(i)x_(i))/(M)=(2md+m(b+d)+3m(d+b))/(6M)=d+(2//3)b` `Y_(c)=(summ_(i)y_(i))/(M)=(2m(o)+m(o)+3MH)/(6m)=H//2` `Z_(c)=0`, because the particles are in X - Y plane we can express the position of centre of mass from the origin using a position vector as `vecr_(c)=X_(c)hati+Y_(c)hatj+Z_(c)hatk,vecr_(c)=(d+(2)/(3)b)hati+(h)/(2)hatj`