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A tangent to the hyperbola `x^(2)-2y^(2)=4` meets x-axis at P and y-aixs at Q. Lines PR and QR are drawn such that OPRQ is a rectangle (where O is origin).Find the locus of R. |
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Answer» Equation of tangent at point `(a sec theta, b tan theta) ` is `(x)/(a) sec theta-(y)/(b) tan theta=1` It meets axis at `P(a cos theta, 0 ) and Q(0, -b cot theta).` Now, rectangle OPRQ is completed. Let the coordinates of point R be (h, k). `therefore" "h=a cos theta and k=-bcot theta` `therefore" "sectheta=(a)/(h) and tan theta=(-b)/(k)` Squaring and subtracting, we get `(a^(2))/(h^(2))-(b^(2))/(k^(2))=1.` So, required locus is `(4)/(x^(2))-(2)/(y^(2))=1`. |
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