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(a) The molar conductivities at infinite dilution of potassium chloride, hydrochloric acid and potassium acetate are 130.1, 379.4 and 95.6 S `cm^(2)mol^(-1)` respectively. Calculate the value of molar conductivity at infinite dilution for acetic acid. (b) If the molar conductivity of given acetic acid solution is 48.5 S `cm^(2)mol^(-1)` at `25^(@)C`, calculate the degree of dissociation of acetic for acetic acid. |
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Answer» Correct Answer - `wedge^(@)=344.9ohm^(-1)cm^(2)mol^(-1);alpha=0.141` `wedge^(@)(CH_(3)COOH)=wedge^(@)(CH_(3)COOK)+wedge^(@)(HCl)-wedge^(@)(KCl)=95.6+379.4-130.1=344.9" S "cm^(2)mol^(-1)` `alpha=(wedge_(m)^(@))/(wedge_(m)^(@))=(48.5)/(344.5)=0.141` |
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