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A thermodynamic process is shown in figure. In process ab, 600 J of heat is added, and in process bd 200 J of heat is added. The total heat added in process acd is

Answer» <html><body><p>550 <a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a><br/>650 J<br/>750 J<br/>850 J</p>Solution :There is no volume change in process ab, so <a href="https://interviewquestions.tuteehub.com/tag/w-729065" style="font-weight:bold;" target="_blank" title="Click to know more about W">W</a> = 0Process <a href="https://interviewquestions.tuteehub.com/tag/bd-389836" style="font-weight:bold;" target="_blank" title="Click to know more about BD">BD</a> occurs at constant pressure, so the work done by the system is<br/> `W = P(V_(2) - V_(1)) = (8 xx 10^(4) Pa)(5 xx 10^(-3)m^(3) - 2 xx 10^(-3) m^(3)) = 240 J` <br/> Thus the total work for abd is W = 240 J and the total heat for abd is Q = 800 J. <br/> `:. Delta U = Q - W = 800 J - 240 J = 560 J` <br/> Because `Delta U` is independent of path, the <a href="https://interviewquestions.tuteehub.com/tag/internal-517481" style="font-weight:bold;" target="_blank" title="Click to know more about INTERNAL">INTERNAL</a> energy change is the same for the path acd as for abd, that is, 560 J. The total work for path acd is<br/> `W = (3 xx 10^(4) Pa)(5 xx 10^(-3)m^(3) - 2 xx 10^(-3) m^(3)) = <a href="https://interviewquestions.tuteehub.com/tag/90-341351" style="font-weight:bold;" target="_blank" title="Click to know more about 90">90</a> J` <br/> `:.` Total heat added in the path acd is<br/> `Q = Delta U + W = 560 J + 90 J = 650 J`</body></html>


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