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A thin circular ring of mass M and radius r is rotating about its ais with an angular speed `omega`. Two particles having mas m each are now attached at diametrically opposite points. The angular speed of the ring will becomeA. `(omega M)/(M+ m)`B. `(omega M)/(M+ 2m)`C. `(omega(M-2m))/(M+2m)`D. `(omega(M+2m))/(M)` |
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Answer» Correct Answer - D |
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