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A thin convex lens made from crown glass `(mu = 3//2)` has focal length `f`. When it is measured in two different liquids having refractive indiced `4//3` and `5//3`, it has the focal length `f_(1)` and `f_(2)` respectively. The correct ralation between the focal lengths isA. `f_(1)=f_(2)ltf`B. `f_(1)gtf` and `f_(2)` becomes negativeC. `f_(2)gtf` and `f_(1)` becomes negativeD. `f_(1)` and `f_(2)` both become negative |
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Answer» Correct Answer - A::B::C::D `(1)/(f)=((3)/(2)-1)((1)/(R_(1))-(1)/(R_(2)))` `(1)/(f)=(1)/(2x)rArr f=2x` here `((1)/(x)=(1)/(R_(1))-(1)/(R_(2)))` `(1)/(f_(1))=((3//2)/(4//3)-1)(1)/(x)` `(1)/(f_(2))=((3//2)/(5//3)-1)((1)/(x)): rArr f_(2)` is iegative `(1)/(f_(1))=(1)/(8x)=(1)/(4(2x))=(1)/(4f)` `rArr f_(1)=4f` Analytically, If a lense is inserted in a denser sourrounding the sing of focal length changes changes and if lens is inserted in a rarer sourrounding, the sign of focal length remain same. If lense is inserted in rarer medium the focal length increases. |
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