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A train travels a distance of 300km at constant speed . If the speed of the train is increased by 5km/h; the journey would have taken 2 hr less. Find the original speed of the train. |
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Answer» Let the usual (original) speed of train x=km/hr and the increased speed =(x+5)km/hr Usual distance covered =300 km `because` Time taken in original speed `=(300)/(x)` and time taken in increased speed `=(300)/(x+5)` But the difference in time in both cases = 2hrs `because(300)/(x)=(300)/(x+5)=2implies(300(x+5-x))/(x(x+5))=2` `impliesx^(2)+5x=750impliesx^(2)+5x-750=0` `implies(x+30)(x-25)=0` `impliesx=-30orx=25` `becausex=25km//hr` (rejecting x=30, because speed cannot be neagtive) `because` The original speed =25 km/hr |
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