A train was moving at the rate of 54kmh^(-1)when brakes were applied. It came to rest within a distance of 225 m. Calculate the retardation produced in the train.

A train was moving at the rate of 54kmh^(-1)when brakes were applied.

1.	A train was moving at the rate of 54kmh^(-1)when brakes were applied. It came to rest within a distance of 225 m. Calculate the retardation produced in the train.
Answer» Solution :The final VELOCITY of the particle v = 0 The initial velocity of the particle `u=54xx(5)/(18)ms^(-1)=15ms^(-1)` `S=225m` Retardation is always against the velocity of the particle. `v^(2)=u^(2)-2AS` `0=(15)^(2)-2a(225)` `450a=225` `a=(225)/(450)ms^(-1)=0.5ms^(-2)` Hence, retardation `=0.5ms^(-2)`