A train was moving at the rate of 54kmh^(-1)when brakes were applied. It came to rest within a distance of 225 m. Calculate the retardation produced in the train.

A train was moving at the rate of 54kmh^(-1)when brakes were applied.

1.	A train was moving at the rate of 54kmh^(-1)when brakes were applied. It came to rest within a distance of 225 m. Calculate the retardation produced in the train.
Answer» <html><body><p></p>Solution :The final <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> of the particle v = 0 <br/> The initial velocity of the particle <br/> `u=54xx(5)/(<a href="https://interviewquestions.tuteehub.com/tag/18-278913" style="font-weight:bold;" target="_blank" title="Click to know more about 18">18</a>)ms^(-1)=15ms^(-1)` <br/> `S=225m` <br/> Retardation is always against the velocity of the particle. <br/> `v^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)=u^(2)-<a href="https://interviewquestions.tuteehub.com/tag/2as-1836799" style="font-weight:bold;" target="_blank" title="Click to know more about 2AS">2AS</a>` <br/> `0=(15)^(2)-2a(225)` <br/> `450a=225` <br/> `a=(225)/(450)ms^(-1)=0.5ms^(-2)` <br/> Hence, retardation `=0.5ms^(-2)`</body></html>