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A transverse harmonic wave on a string is described by y(x,t)=3.0 sin (36t+0.018x +pi//4), where x and y are in cm and t is in s. The positive direction of x is from left to right.

Answer»

The wave is travelling from right to left.
The speed of the wave is `20m//s`
Frequency of the wave is 5.7 Hz
The least distance betweent two successive crests in the wave is 2.5cm

Solution :The GIVEN equation is`y(x,t)=3.0sin [36t+0.018x+(pi)/(4)]`
(a As positive DIRECTION is from left to right and x positive, therefore, wave is travelling from right to left.
(b) COMPARE the given equation with the standard form
`y=rsin[(2pit)/(T)+(2pix)/(lambda0+phi)]`
`(2PI)/(T)=36, (2pi)/(LAMBDA)=0.018`
speed of wave, `upsilon=(lambda)/(T)=(36)/(0.018)=2000cm//s=20m//s`
(c) Again, `T=(2pi)/(36)=(pi)/(18)`
Frequency, `v=(1)/(V)=(18)/(pi)Hz=5.7Hz`


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