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A transverse harmonic wave on a string is described by y(x,t)=3.0 sin (36t+0.018x +pi//4), where x and y are in cm and t is in s. The positive direction of x is from left to right.

Answer» <html><body><p>The wave is travelling from right to left. <br/>The speed of the wave is `20m//s`<br/>Frequency of the wave is 5.7 Hz<br/>The least distance betweent two successive crests in the wave is 2.5cm</p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> equation is`y(x,t)=3.0sin [36t+0.018x+(pi)/(4)]` <br/> (a As positive <a href="https://interviewquestions.tuteehub.com/tag/direction-1696" style="font-weight:bold;" target="_blank" title="Click to know more about DIRECTION">DIRECTION</a> is from left to right and x positive, therefore, wave is travelling from right to left. <br/> (b) <a href="https://interviewquestions.tuteehub.com/tag/compare-11929" style="font-weight:bold;" target="_blank" title="Click to know more about COMPARE">COMPARE</a> the given equation with the standard form <br/> `y=rsin[(2pit)/(T)+(2pix)/(lambda0+phi)]` <br/> `(<a href="https://interviewquestions.tuteehub.com/tag/2pi-1838601" style="font-weight:bold;" target="_blank" title="Click to know more about 2PI">2PI</a>)/(T)=36, (2pi)/(<a href="https://interviewquestions.tuteehub.com/tag/lambda-539003" style="font-weight:bold;" target="_blank" title="Click to know more about LAMBDA">LAMBDA</a>)=0.018` <br/> speed of wave, `upsilon=(lambda)/(T)=(36)/(0.018)=2000cm//s=20m//s` <br/> (c) Again, `T=(2pi)/(36)=(pi)/(18)` <br/> Frequency, `v=(1)/(V)=(18)/(pi)Hz=5.7Hz`</body></html>


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