InterviewSolution
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InterviewSolution
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A tuning fork C produces 8 beats per second with another tuning fork D of frequency 340 Hz. When the prongs of tuning fork C are filed a little, the number of beats produced per second decreases to 4. Find the frequency of tuning fork C before filing its prongs. |
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Answer» The frequency of timing fork D is 340 Hz. Let n be the frequency of tuning fork C. Since tuning forks C and D produce 8 beats per second when sounded together, n – 340 = 8 or 340 – n = 8 ∴ n = 348 Hz or 332 Hz When the prongs of a tuning fork are filed a little, its frequency increases. Let n’ be its frequency after filing : n’ > n. It is given that the beat frequency is reduced from 8 Hz to 4 Hz. If n was 348 Hz, n’ will be more than 348 Hz. Hence, the beat frequency should increase. Hence, n ≠ 348 Hz. ∴ n = 332 Hz |
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