A U-tube is supoorted with its limbs vertical and is partly filled with water. If internal diameter of the limbs are 1xx10^(-2)m and 1xx10^(-4) m respectively what will be the difference in heights of water columns in the two limbs (Surface tension of water is 0.07Nm^(-1))

A U-tube is supoorted with its limbs vertical and is partly filled wit

1.	A U-tube is supoorted with its limbs vertical and is partly filled with water. If internal diameter of the limbs are 1xx10^(-2)m and 1xx10^(-4) m respectively what will be the difference in heights of water columns in the two limbs (Surface tension of water is 0.07Nm^(-1))
Answer» <html><body><p></p>Solution :Surface <a href="https://interviewquestions.tuteehub.com/tag/tension-1241727" style="font-weight:bold;" target="_blank" title="Click to know more about TENSION">TENSION</a> `S=0.07Nm^(-1)` <br/> Densith `rho=1000 kgm^(-3),<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>=9,8ms^(-2)` <br/> Angle of contact `theta=0^(@)` <br/> <a href="https://interviewquestions.tuteehub.com/tag/radius-1176229" style="font-weight:bold;" target="_blank" title="Click to know more about RADIUS">RADIUS</a> `r_(1)=0.5xx10^(-2)m, ` Radius `r_(2)=0.5xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)m` <br/>Let `h_(1)` be the height of water in the limb of radius `r_(1)` <br/> Then `h_(1)=(2Scos theta)/(r_(1)rho g)=(2xx0.07xxcos 0^(@))/(0.5xx10^(-2)xx1000xx9.8)m` <br/> `=2.86xx10^(-3)m` <br/> similarly `h_(2)=2.86xx10^(-1)m` <br/> Difference in heights <br/> `=h_(2)-h_(1)=2.86xx10^(-1)m-2.86xx10^(-3)m` <br/> `=(0.286-0.00286)m=0.283m`</body></html>