A U-tube is supoorted with its limbs vertical and is partly filled with water. If internal diameter of the limbs are 1xx10^(-2)m and 1xx10^(-4) m respectively what will be the difference in heights of water columns in the two limbs (Surface tension of water is 0.07Nm^(-1))

A U-tube is supoorted with its limbs vertical and is partly filled wit

1.	A U-tube is supoorted with its limbs vertical and is partly filled with water. If internal diameter of the limbs are 1xx10^(-2)m and 1xx10^(-4) m respectively what will be the difference in heights of water columns in the two limbs (Surface tension of water is 0.07Nm^(-1))
Answer» Solution :Surface TENSION `S=0.07Nm^(-1)` Densith `rho=1000 kgm^(-3),G=9,8ms^(-2)` Angle of contact `theta=0^(@)` RADIUS `r_(1)=0.5xx10^(-2)m, ` Radius `r_(2)=0.5xx10^(-4)m` Let `h_(1)` be the height of water in the limb of radius `r_(1)` Then `h_(1)=(2Scos theta)/(r_(1)rho g)=(2xx0.07xxcos 0^(@))/(0.5xx10^(-2)xx1000xx9.8)m` `=2.86xx10^(-3)m` similarly `h_(2)=2.86xx10^(-1)m` Difference in heights `=h_(2)-h_(1)=2.86xx10^(-1)m-2.86xx10^(-3)m` `=(0.286-0.00286)m=0.283m`