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A uniform circular disc of radius a is taken. A circular portion of radius b has been removed from it as shown in the figure. If the center of hole is at a distance c from the center of the disc, the distance `x_(2)` of the center of mass of the remaining part from the initial center of mass O is given by A. `(pib^(2))/(a^(2) - c^(2))`B. `(cb^(2))/(a^(2)-b^(2))`C. `(pic^(2))/(a^(2)-b^(2))`D. `(ca^(2))/((c^(2)-b^(2)))` |
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Answer» Correct Answer - B Center of mass of whole system was at point O. Hence `x_(2)(pia^(2) - pib^(2)) = c(pib^(2)) rArr x_92) = (cb^(2))/(a^(2)-b^(2))` |
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