InterviewSolution
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InterviewSolution
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A uniform magnetic field of `3000G` is established along the positive z-direction. A rectangular loop of sides `10cm` and `5cm` carries a current `12A`. What is the torque on the loop in the different cases shown in the figure. What is the force on each case? Which case corresponds to stable equilibrium? |
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Answer» Correct Answer - (a) `1*8xx10^-2Nm` (b) Angle between area vector `vecA` and `vecB` is `0^@` or `180^@` (c) Loop will be in stable equilibrium if area vector `vecA` is parallel to magnetic field `vecB` and in unstable equilibrium when `vecA` is antiparallel to `vecB` Here, `B=3000G=0*3T`, `I=12A` `A=10xx5=50cm^2=50xx10^-4m^2`. (a) `tau_(max.)=IAB sin 90^@=12xx(50xx10^-4)xx0*3` `=1*8xx10^-2Nm` (b) Torque is zero when `sin theta=0` i.e. `theta=0^@` or `180^@` (c) Loop will be in stable equilibrium if `vecA` is parallel to `vecB` and in unstable equilibrium if `vecA` is antiparallel to `vecB`. |
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