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A uniform piece of metal sheet is cut in the form as shown in the fig. Locate the center of mass of the piece.

Answer» <html><body><p></p>Solution :<img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_MP2_C07_SLV_020_S01.png" width="80%"/> <br/> Let the mass per unit area be `<a href="https://interviewquestions.tuteehub.com/tag/sigma-1207107" style="font-weight:bold;" target="_blank" title="Click to know more about SIGMA">SIGMA</a>` We divide the <a href="https://interviewquestions.tuteehub.com/tag/structure-1230280" style="font-weight:bold;" target="_blank" title="Click to know more about STRUCTURE">STRUCTURE</a> into parts 1, 2 and 3. The mass of <a href="https://interviewquestions.tuteehub.com/tag/part-596478" style="font-weight:bold;" target="_blank" title="Click to know more about PART">PART</a> 1 is 300 `sigma`, mass of part 2 is 200 `sigma` and that of part 3 in 100 `sigma`. The coordinates of centre of mass of part 1 are (5, 15), that of part 2 are (20,5), and that of part 3 are (15, 25) <br/> Using the Eq. <br/> `x_(cm)=((300sigma)5+(200sigma)20+(100sigma)15)/(600sigma)~~11.7` <br/> `y_(cm)=((300sigma)15+(200sigma)5+(100sigma)25)/(600sigma)~~13.3` <br/> In vector notation `barr_(cm)=11.7hati+13.3hatj`</body></html>


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