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A uniform rope of length 10 m and mass 3 kg hangs vertically from a rigid support. A block of mass 1 kg is attached to the free end of the rople. A transverse pulse of wavelength 0.05 m is produced at the lower end of the rope. The wavelength of the pulse when it reaches the top of the rope is

Answer» <html><body><p>0.10 m<br/>0.12 m<br/>0.16 m<br/>0.18 m </p>Solution :Since the <a href="https://interviewquestions.tuteehub.com/tag/rope-1191046" style="font-weight:bold;" target="_blank" title="Click to know more about ROPE">ROPE</a> has a mass, the tension <a href="https://interviewquestions.tuteehub.com/tag/along-1974109" style="font-weight:bold;" target="_blank" title="Click to know more about ALONG">ALONG</a> its length is <a href="https://interviewquestions.tuteehub.com/tag/variable-1442996" style="font-weight:bold;" target="_blank" title="Click to know more about VARIABLE">VARIABLE</a>. At the top end, its tension is `(3+1)g N` or `4g N`. At the bottom end, its tension is 1g N. <br/> Now, <a href="https://interviewquestions.tuteehub.com/tag/speed-1221896" style="font-weight:bold;" target="_blank" title="Click to know more about SPEED">SPEED</a> of the <a href="https://interviewquestions.tuteehub.com/tag/transverse-1426606" style="font-weight:bold;" target="_blank" title="Click to know more about TRANSVERSE">TRANSVERSE</a> wave on the string, `c=sqrt((T)/(mu))` <br/> `upsilonlambda=sqrt((T)/(mu))""(because c=upsilonlambda)` <br/> As frequency `upsilon and mu`, the linear density are constant, so `sqrt(T)/(lambda)`is a constant.</body></html>


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