A vessel at 1000 K contains carbon dioxide with a pressure of 0.5 atm. Some of the carbon dioxide is converted to carbon monoxide on addition of graphite. Calculate the value of K it the total pressure at equilibrium is 0*8 atm.

A vessel at 1000 K contains carbon dioxide with a pressure of 0.5 atm.

1.	A vessel at 1000 K contains carbon dioxide with a pressure of 0.5 atm. Some of the carbon dioxide is converted to carbon monoxide on addition of graphite. Calculate the value of K it the total pressure at equilibrium is 0*8 atm.
Answer» <html><body><p></p>Solution :`CO_(2) (<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>) + C (s) hArr 2 CO (g)` <br/> Suppose decreasein pressure of `CO_(2)` after reaction = p atm <br/> Then increase in pressure due to CO= 2 p <br/> Pressure of `CO_(2)` at equilibrium `=(0.<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a> - p)` atm <br/> `:." Final <a href="https://interviewquestions.tuteehub.com/tag/total-711110" style="font-weight:bold;" target="_blank" title="Click to know more about TOTAL">TOTAL</a> pressure " (0.5- p) + 2p = 05 + p = 0.<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a> " atm"`(Given) <br/>`:. p= 03 " atm.Hence we have "` <br/> `p_(CO_2) = 05 - 03 = 02 " atm "` <br/> `and ""p_(CO) = 2 xx 03 = 06 " atm" ` <br/> `:. K = (P_(cO)^(2))/P_(CO_(2)) = (0.6)^(2)/(02) = <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>*8`</body></html>