A vessel at 1000 K contains carbon dioxide with a pressure of 0.5 atm. Some of the carbon dioxide is converted to carbon monoxide on addition of graphite. Calculate the value of K it the total pressure at equilibrium is 0*8 atm.

A vessel at 1000 K contains carbon dioxide with a pressure of 0.5 atm.

1.	A vessel at 1000 K contains carbon dioxide with a pressure of 0.5 atm. Some of the carbon dioxide is converted to carbon monoxide on addition of graphite. Calculate the value of K it the total pressure at equilibrium is 0*8 atm.
Answer» Solution :`CO_(2) (G) + C (s) hArr 2 CO (g)` Suppose decreasein pressure of `CO_(2)` after reaction = p atm Then increase in pressure due to CO= 2 p Pressure of `CO_(2)` at equilibrium `=(0.5 - p)` atm `:." Final TOTAL pressure " (0.5- p) + 2p = 05 + p = 0.8 " atm"`(Given) `:. p= 03 " atm.Hence we have "` `p_(CO_2) = 05 - 03 = 02 " atm "` `and ""p_(CO) = 2 xx 03 = 06 " atm" ` `:. K = (P_(cO)^(2))/P_(CO_(2)) = (0.6)^(2)/(02) = 1*8`