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A vessel at 1000 K contains CO_(2) with a pressure of 0.5 atm. Some of CO_(2) is converted into CO on addtion of graphite. The value of K' at equilibrium when total pressure is 0.8 atm will be

Answer» <html><body><p>0.18 atm<br/>1.8 atm<br/>2 atm<br/>1 atm</p>Solution :`underset(0.5)(CO_(2))+C_((s)) harr 2CO` <br/> at <a href="https://interviewquestions.tuteehub.com/tag/eqm-446398" style="font-weight:bold;" target="_blank" title="Click to know more about EQM">EQM</a> 0.5-P`""<a href="https://interviewquestions.tuteehub.com/tag/2p-300467" style="font-weight:bold;" target="_blank" title="Click to know more about 2P">2P</a>` <br/> P=0.3 <br/> `K=((0.6)^(2))/((0.2))=1.8`atm</body></html>


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