A vessel contains 0.25 moles of Helium and0.15 moles of neon at 298K and 2.4 atmosphere pressure. Calculate the partial pressure of each gas in the mixture.

A vessel contains 0.25 moles of Helium and0.15 moles of neon at 298K a

1.	A vessel contains 0.25 moles of Helium and0.15 moles of neon at 298K and 2.4 atmosphere pressure. Calculate the partial pressure of each gas in the mixture.
Answer» Solution :TOTAL PRESSURE .P.=2.4atm No. of moles of He=0.25 No. of moles of Ne=0.15 Total moles of n=0.25+0.15=0.4 Partial pressure = Total pressure X Mole-fraction `P_(He) = (n_(He))/(n) xx P = (0,.25)/(0.4) xx 2.4 = 1.5 atm` `P_(N e) = (n_(N e))/(n) xx P = (0.15)/(0.4) xx 2.4 = 0.9 atm`.