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A vessel contains a mixture of `7 g` of nitrogen and `11 g` carbon dioxide at temperature ` T = 290 K`. If pressure of the mixure is `1 atm (= 1.01 xx 10^5 N//m^2)`, calculate its dencity `(R = 8.31 J//mol - K)`. |
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Answer» Correct Answer - A::C `(n_1) =` number of moles of nitrogen = `7/(28) = 1/4` `(n_2) =` number of moles of `CO_2 = (11)/(44) = 1/4` `M = (n_1 M_1 + n_2 M_2)/(n_1 + n_2)` = `((1/4)(28)+(1/4)(44))/((1/4)+(1/4))= 36` Now, `rho = (RM)/(RT)` = `((1.01 xx 10^5)(36 xx 10^-3))/((8.31)(290))` = `1.5 kg //m^3`. |
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