A vessel contains a mixture of equal masses of helium and oxygen at a pressure of 600 torr. Calculate the partial pressures of components in the mixture.

A vessel contains a mixture of equal masses of helium and oxygen at a

1.	A vessel contains a mixture of equal masses of helium and oxygen at a pressure of 600 torr. Calculate the partial pressures of components in the mixture.
Answer» Solution :Let the mass of each component gas is x. Total number of moles in the mixture = `(XG " of " He)/(4G " of " mol^(-1)) + (xg " of " O_2)/(32 g " of " mol^(-1)) = (9x)/(32 g mol^(-1))` Partial pressure = pressure of the mixture x mole FRACTION Partial pressure of He `= 600 xx (x//4)/(9x//32) = 600 xx 8/9` `= 5333.33"TORR"` Partial pressure of `O_2 = 600 xx (x//32)/(9x//32)` `= 600 xx 1/9 = 66.67` torr (or) Partial pressure of `O_2 = 600 - 533.37 ` = 66.67 torr