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A vessel contains helium and methane in 4:1 mole ratio at 20 bar pressure. Find the ratio of initial rates of effusion through a small aperture.

Answer» <html><body><p>&lt;<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>&gt;</p>Solution :Ratio of moles of He and `CH_(4)` = 4 : 1 <br/> Ratio of partialpressure of He and `Ch_(4) = 4 :1` <br/> Total pressure of the mixture = <a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a> bar <br/> Partial pressure of He ` = 20 xx (4)/(5) = 16` bar <br/> partial pressure of `CH_(4) = 20 xx (1)/(5) =4 ` bar <br/> Ratio of intial <a href="https://interviewquestions.tuteehub.com/tag/rates-25465" style="font-weight:bold;" target="_blank" title="Click to know more about RATES">RATES</a> of effusion is ` (r_(1))/(r_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)) = (P_(1))/(P_(2)) sqrt((M_(2))/(M_(1))) = (16)/(4) sqrt((16)/(4)) = (4)/(1) sqrt((4)/(1))` <br/> The ratio of <a href="https://interviewquestions.tuteehub.com/tag/initial-499269" style="font-weight:bold;" target="_blank" title="Click to know more about INITIAL">INITIAL</a> rates of effusion of gases, helium and methane ` =4 sqrt(4) : 1 = 8 : 1`</body></html>


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