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A vessel contains helium and methane in 4:1 mole ratio at 20 bar pressure. Find the ratio of initial rates of effusion through a small aperture. |
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Answer» <P> Solution :Ratio of moles of He and `CH_(4)` = 4 : 1Ratio of partialpressure of He and `Ch_(4) = 4 :1` Total pressure of the mixture = 20 bar Partial pressure of He ` = 20 xx (4)/(5) = 16` bar partial pressure of `CH_(4) = 20 xx (1)/(5) =4 ` bar Ratio of intial RATES of effusion is ` (r_(1))/(r_(2)) = (P_(1))/(P_(2)) sqrt((M_(2))/(M_(1))) = (16)/(4) sqrt((16)/(4)) = (4)/(1) sqrt((4)/(1))` The ratio of INITIAL rates of effusion of gases, helium and methane ` =4 sqrt(4) : 1 = 8 : 1` |
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