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A vessel of 120 mL capacity contains a certain amount of gas at 35^(@)C and 1.2 bar pressure. The gas 1p transferred to another vessel of volume 180 mL at 35^(@) C. What would be its pressure ?

Answer»

Solution :`P_(1)=1*2` bar `P_(2) =?, v_(1)=120 ML, v_(2)=180 mL`
TEMPERATURE contant.
According contant.
According to Boyle.s law `P_(1)V_(1)=P_(2)V_(2) `or
`P_(2) =(P_(1)V_(1))/(V_(2))=(1*2 "bar" xx12 mL)/(180mL)=0*8 "bar"`.


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