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A vessel of 120 mL capacity contains a certain amount of gas at 35^(@)C and 1.2 bar pressure. The gas 1p transferred to another vessel of volume 180 mL at 35^(@) C. What would be its pressure ?

Answer» <html><body><p></p>Solution :`P_(1)=1*2` bar `P_(2) =?, v_(1)=<a href="https://interviewquestions.tuteehub.com/tag/120-270396" style="font-weight:bold;" target="_blank" title="Click to know more about 120">120</a> <a href="https://interviewquestions.tuteehub.com/tag/ml-548251" style="font-weight:bold;" target="_blank" title="Click to know more about ML">ML</a>, v_(2)=<a href="https://interviewquestions.tuteehub.com/tag/180-279527" style="font-weight:bold;" target="_blank" title="Click to know more about 180">180</a> mL` <br/> <a href="https://interviewquestions.tuteehub.com/tag/temperature-11887" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATURE">TEMPERATURE</a> contant.<br/> According contant. <br/> According to Boyle.s law `P_(1)V_(1)=P_(2)V_(2) `or <br/> `P_(2) =(P_(1)V_(1))/(V_(2))=(1*2 "bar" xx12 mL)/(180mL)=0*8 "bar"`.</body></html>


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