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A vessel of 120 mL capacity contains a certain amount of gas at 35^(@)C and 1.2 bar pressure. The gas is transferred to another vessel of volume 180 mL at 35^(@)C. What would be its pressure ? |
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Answer» <P> Solution :`V_(1)=120 ML,""P_(1)=1.2 bar, "" T_(1)=35^(@)C``V_(2)=180 mL, ""P_(2)=?, ""T_(2)=35^(@)C` As temperature remains CONSTANT,APPLYING Boyle's law, `P_(1)V_(1)=P_(2)V_(2)` `(1.2"bar")(120 mL)=P_(2)(180 mL) or P_(2)=0.8 "bar"` |
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