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A vessel of 120 mL capacity contains a certain amount of gas at 35^(@)C and 1.2 bar pressure. The gas is transferred to another vessel of volume 180 mL at 35^(@)C. What would be its pressure ? |
Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>></p>Solution :`V_(1)=<a href="https://interviewquestions.tuteehub.com/tag/120-270396" style="font-weight:bold;" target="_blank" title="Click to know more about 120">120</a> <a href="https://interviewquestions.tuteehub.com/tag/ml-548251" style="font-weight:bold;" target="_blank" title="Click to know more about ML">ML</a>,""P_(1)=1.2 bar, "" T_(1)=35^(@)C` <br/> `V_(2)=180 mL, ""P_(2)=?, ""T_(2)=35^(@)C` <br/> As temperature remains <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a>,<a href="https://interviewquestions.tuteehub.com/tag/applying-1982651" style="font-weight:bold;" target="_blank" title="Click to know more about APPLYING">APPLYING</a> Boyle's law, `P_(1)V_(1)=P_(2)V_(2)` <br/> `(1.2"bar")(120 mL)=P_(2)(180 mL) or P_(2)=0.8 "bar"`</body></html> | |